Answer:
D) magnitude: 4 × 10^4 N
direction: north
Explanation:
q₁ = magnitude of negative charge = 6 x 10⁻⁶ C
q₂ = magnitude of positive charge = 3 x 10⁻⁶ C
r = distance between the two charges = 0.002 m
Magnitude of electric force between the two charges is given as
F = k q₁ q₂/r²
where k = constant = 9 x 10⁹
inserting the values
F = (9 x 10⁹) (6 x 10⁻⁶) (3 x 10⁻⁶)/(0.002)²
F = 4 x 10⁴ N
magnitude : 4 x 10⁴ N
Direction : North
we know that a negative charge pulls a positive charge towards it. the negative charge "q₁" is north of the positive charge. hence the charge q₁ apply force on charge q₂ in north direction.
