Question

In January, Bangkok is hotter than Cape Town while Cape Town is hotter than Moscow. Which inequality correctly compares the temperatures of the three cities?

A.
Bangkok's temperature < Cape Town's temperature < Moscow's temperature
B.
Bangkok's temperature < Moscow's temperature < Cape Town's temperature
C.
Bangkok's temperature > Moscow's temperature > Cape Town's temperature
D.
Bangkok's temperature > Cape Town's temperature > Moscow's temperature

Answer 1

Answer: The correct option is D.

Explanation:

It is given that in January, Bangkok is hotter than Cape Town while Cape Town is hotter than Moscow.

Since Bangkok is hotter than Cape Town, it means the temperature of Bangkok is more than  or greater than the Cape town.

$\text{Bangkok's temperature}>\text{Cape Town's temperature}$  .... (1)

Since Cape Town is hotter than Moscow, it means the temperature of Cape town is more than or greater than the Moscow.

$\text{Cape Town's temperature}>\text{Moscow's temperature}$    ..... (2)

From equation (1) and (2) we get,

$\text{Bangkok's temperature}>\text{Cape Town's temperature}>\text{Moscow's temperature}$

Therefore, the correct option is D.

Answer 2

The Correct answer is d