Respuesta :
Use the table of standardized normal cumulative function.
Look up the corresponding x' for the value z=0.9332: I found x'=0.8232 (approximately).
We know that x'=1.5x, so x = 0.8232/1.5 = 0.5488
The value of "x" will be "0.5488".
According to the question,
- z = 0.9332
By using the standardized normal cumulative function,
- [tex]x' = 0.8132[/tex]
We know,
→ [tex]x' = 1.5 x[/tex]
then,
→ [tex]x = \frac{x'}{1.5}[/tex]
By substituting the value, we get
[tex]= \frac{0.8232}{1.5}[/tex]
[tex]= 0.5488[/tex]
Hence, the above answer is appropriate.
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