Question

What is the molarity of an hcl solution if 27.3 ml of it neutralizes 134.5 ml of 0.0165 m ba(oh)2?

Answer 1

Hey there!:

2 HCl + Ba(OH)2 = BaCl2 + 2 H2O

Moles Ba(OH)2 = 0.1345L*0.0165M=0.002219 moles

Moles OH= 2*moles Ba(OH)2= 0.004438 moles

It are required the same amount of hydrogen moles to neutralizes the solution so  ;

Moles H=0.004438, and the same amount of moles HCl= 0.004438 moles divided by the volume

M=0.004438 /0.0273= 0.163 M

Hope that helps!

Answer 2

The molarity of an HCl solution will be "0.163 M".

According to the given question,

→ $Moles \ Ba(OH)_2 = 0.1345 \ L\times 0.0165 \ M$

                              $= 0.002219 \ moles$

→ $Moles \ OH = 2\times moles \ Ba(OH)_2$

                     $=2\times 0.002219 \ moles$

hence,

→ The molarity of an HCl solution will be:

= $\frac{0.004438}{0.0273}$

= $0.163 \ M$

Thus the above answer is correct.

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