Question

Ne(g) effuses at a rate that is ______ times that of kr(g) under the same conditions.

Answer 1

Answer:

                  Ne effuses at a rate that is 2.05 times that of Kr under the same conditions

Explanation:

                  According to Graham's Law of Effusion, "the rate of effusion of a gas is inversely proportional to the square root of its density or molar mass".

Mathematically,

                                      Rₐ / Rₓ  =  $\sqrt{Mx / Ma}$    ----- (1)

Where;

           Rₐ  =  Rate of effusion of Ne

           Rₓ  =  Rate of effusion of Kr

           Mₐ  =  Molar Mass of Ne  =  20.18 g.mol⁻¹

           Mₓ  =  Molar Mass of Kr  =  84.80 g.mol⁻¹

Putting values in equation 1,

                                      Rₐ / Rₓ  =  $\sqrt{84.80 / 20.18}$

                                      Rₐ / Rₓ  =  $\sqrt{4.20}$

                                      Rₐ / Rₓ  =  2.05

Result:

         Hence, Ne effuses 2.05 times faster than Kr.