Question

In January, Bangkok is hotter than Cape Town while Cape Town is hotter than Moscow. Which inequality correctly compares the temperatures of the three cities?

Answer 1

Answer-

$T_{Bangkok}>T_{Cape\ Town}>T_{Moscow}$

Solution-

From general laws of physics, we know that, the more the heat content in a body, the more is the temperature. i.e as the temperature increases the body or system gets headed, vice-versa.

Let's assume,

Temperature of Bangkok = T₁

Temperature of Cape Town = T₂

Temperature of Moscow = T₃

As, Bangkok is hotter than Cape Town,

$\Rightarrow T_1>T_2$  ------------------------1

Then, Cape Town is hotter than Moscow,

$\Rightarrow T_2>T_3$  -----------------------2

Combing these two equations,

$\Rightarrow T_1>T_2>T_3$

Therefore, this is the inequality that correctly compares the temperatures of the three cities.