Respuesta :
Alright, lets get started.
A light private plane can fly 120 mph in still air.
Suppose the speed of wind = x mph
Against the wind, speed of plane will be = 120-x
With the wind, speed of plane will be = 120+x
Flying against the wind, the plane can fly 320 miles, so time taken will be
t = [tex]\frac{320}{120-x}[/tex]
With the wind, the plane can fly 640 miles, so time taken will be
[tex]t = \frac{640}{120+x}[/tex]
Both times are given same, so
[tex]\frac{320}{120-x}= \frac{640}{120+x}[/tex]
Cross multiplying
[tex]320(120+x) = 640(120-x)[/tex]
Dividing from 320
[tex]120+x = 2(120-x)[/tex]
[tex]120+x = 240-2x[/tex]
[tex]3x = 120[/tex]
x = 40 mph
So, the speed of the wind is 40 mph. : Answer
Hope it will help :)