Consider the equation [tex]5+\dfrac{4}{7}\left(21+3x\right)=41.[/tex]
1. Multiply this equation by 7:
[tex]5\cdot 7+\dfrac{4}{7}\cdot 7 (21+3x)=41\cdot 7,\\\\35+4(21+3x)=287.[/tex]
2. Eliminate brackets:
[tex]35+4\cdot 21+4\cdot 3x=287,\\\\35+84+12x=287.[/tex]
3. Separate terms with x into the left side and without x into the right side:
[tex]12x=287-35-84,\\\\12x=168.[/tex]
4. Find x:
[tex]x=168:12,\\ \\x=14.[/tex]
Answer: x=14.
