Question

A baseball stadium holds 15,002 seats. The lower level has 50 fewer than three times as many seats as the upper level. The middle level has 40 more than twice as many seats as the upper level. x + (2x + 40) + (3x – 50) = 15,002 The upper level has(             ) seats. pls solve fast

Answer 1

Let Upper Level = x

Middle level = 2x+40

Lower level = 3x-50

The sum of those 3 has to equal 15,002 seats.

X + (2x+40) + 3x-50) = 15, 002

Simplify the left side by combining the like terms:

6x - 10 = 15,002

Add 10 to each side:

6x = 15,012

Divide both sides by 6 to solve for x:

X = 15012 / 6

X = 2502

The upper level is X , so has 2,502 seats.

Middle level = 2x +40 = 2(2502) +b40 = 5004 + 40 = 5,044 seats

Lower level = 3x-50 = 3(2502) -50 = 7506 - 50 = 7,456 seats

Answer 2

The number of seats in the upper level is required.

The number of seats the upper level has is 2502.

Let the number of upper level seats be $x$

The lower level seats are $3x-50$

The middle level seats are $2x+40$

The total number of seats are 15002

So,

$x+3x-50+2x+40=15002\\\Rightarrow 6x-10=15002\\\Rightarrow x=\dfrac{15002+10}{6}\\\Rightarrow x=2502$

The number of seats the upper level has is 2502.

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