Answer: [tex]\dfrac{1}{6}[/tex]
Step-by-step explanation:
Given statement : Marcus tosses a coin and spins a spinner numbered from 1 to 3.
Let A be the event of getting a head while tossing a coin.
Total faces on coin=2
Then [tex]P(A)=\dfrac{1}{2}[/tex]
Let B be the event of spinner lands on 1.
Total sections on spinner = 3
Then [tex]P(B)=\dfrac{1}{3}[/tex]
Since both events are independent of each other.
Therefore, the probability the coin lands heads up and the spinner lands on 1 = [tex]P(A)\timesP(B)=\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{1}{6}[/tex]
Hence, the probability the coin lands heads up and the spinner lands on 1 = [tex]\dfrac{1}{6}[/tex]
