Respuesta :
Distance to checkpoint A from starting line = 20 yards.
Then from A to B distance = 12 yards.
Let us take starting point C.
So, it would make a right triangle.
We have AB = 12, AC = 20, we need to find BC, that is Hypotenuse of the right triangle.
According to Pythagoras theorem:
[tex]BC^2 = AB^2+AC^2[/tex]
[tex]BC^2 = 12^2+20^2[/tex]
[tex]BC^2 = 144 +400 = 544[/tex]
[tex]BC= \sqrt{544}[/tex]
BC = 23.32.
Therefore, 23.32 yards is the distance from Checkpoint B to the starting line.
Answer:
The shortest distance between checkpoint A and checkpoint B is 23.33 yards.
Step-by-step explanation:
We are given the following information in the question:
Let O be the starting point.
Distance between the starting point and checkpoint A = 20 yards
To reach checkpoint B, one need to take a turn and let it be a 90 degrees turn toward right or left.
Distance between checkpoint A and checkpoint B = 12 yards
In order to find the shortest distance between the checkpoint A and checkpoint B, the displacement, we use the Pythagoras theorem.
Statement:
In a right angled triangle:
[tex](Side 1)^2 + (Side 2)^2 = (Hypotenuse)^2[/tex]
[tex](OA)^2 + (AB)^2 = (AB)^2\\(20)^2 + (12)^2 = (AB)^2\\400 + 144 = (AB)^2\\(AB)^2 = 544\\AB = \sqrt{544} \approx 23.33[/tex]
Hence, the shortest distance between checkpoint A and checkpoint B is 23.33 yards.