Question

When an object is dropped on the moon, it travels approximately

0.8t^2 meters in t seconds. Suppose an astronaut drops a moon rock from a height of 2 meters. Find the speed of the rock after 1 second.

Answer 1

Answer:

1.6 meters per second.

Step-by-step explanation:

We have been given an position function $P(t)=0.8t^{2}$ and we are asked to find the speed of the rock after 1 second.

Derivative of this function will give us speed function.

$S(t)=2\cdot 0.8\cdot t$

$S(t)=1.6\cdot t$

Now let us find derivative when t=1,

$S(1)=1.6\cdot 1=1.6$

Therefore, the speed of the rock after 1 second will be 1.6 meters per second.