Respuesta :
Answer:
Explanation:
When potassium chloride reacts with lead acetate in aqueous medium, it gives white precipitate of lead chloride and potassium acetate in aqueous medium as a product.
As shown in chemical reaction given below:
[tex]2KCl(aq)+Pb(CH_3COO)_{2}(aq)\rightarrow PbCl_2(s)+2(CH_3COO)^{-}K^{+}(aq)[/tex]
Answer: The chemical equation is written below.
Explanation:
When potassium chloride reacts with lead (II) acetate, it leads to the formation of two products.
The chemical equation for the reaction of potassium chloride and lead (II) acetate follows:
[tex]2KCl(aq.)+Pb(CH_3COO)_2(aq.)\rightarrow 2CH_3COOK(aq.)+PbCl_2(s)[/tex]
By Stoichiometry of the reaction:
2 moles of aqueous solution of potassium chloride reacts with 1 mole of aqueous solution of lead (II) acetate to produce 2 moles of aqueous solution of potassium acetate and 1 mole of solid lead (II) chloride.