ANSWER
Yes it is very true
EXPLANATION
If the two equations intersect at [tex](50,60)[/tex] then this point must satisfy the two equations.
[tex]3x+2y=270---(1)[/tex]
We substitute [tex](50,60)[/tex] in to erquation (1)
[tex]3(50)+2(60)=270[/tex]
[tex]150+120=270[/tex]
[tex]270=270[/tex]
[tex]y=\frac{4}{5}x+20 ---(2)[/tex]
We now substitute [tex](50,60)[/tex] in to erquation (2) also
[tex]60=\frac{4}{5}(50)+20[/tex]
[tex]60=40+20[/tex]
[tex]60=60[/tex]
Since the point satisfy all the two equations, it is true that they intersect at [tex](60,50)[/tex]
