we are given
total number of candidates =17
Nine of the candidates are members of the debate team
number of debate candidates=9
(a)
Total number of officers=4
we can use combination formula
[tex]nCr=\frac{n!}{r!(n-r)!}[/tex]
So, the number of ways in which 4 people can be selected from 17 people is
[tex]17C4=\frac{17!}{4!(17-4)!}[/tex]
now, we can simplify it
[tex]17C4=2380[/tex]
and the number of ways in which 4 people can be selected from the debate team of 9 is
[tex]9C4=\frac{9!}{4!(9-4)!}[/tex]
now, we can simplify it
[tex]9C4=126[/tex]
so, P(all offices filled by debate team members) is
[tex]=\frac{126}{2380}[/tex]
so, P(all offices filled by debate team members) is 0.0529..........Answer
(b)
non-debate team is 17-9=8
number of ways in which 4 people can be selected from the non-debate team of 8 is
[tex]8C4=\frac{8!}{4!(8-4)!}[/tex]
[tex]8C4=70[/tex]
Probability that none of the office is filled by the debate team is
[tex]=\frac{70}{2380}[/tex]
[tex]=0.029[/tex]..............Answer