Question

Strep throat is caused by Streptococcus bacteria. The amount of bacteria multiplies at a rate of 10^13 per 10^2 hrs. What is the total amount of bacteria present after 10^3 hour?

Answer 1

Answer: The total amount of bacteria present after $10^3$ hours is $10^{14}$.

Explanation:

It is given that the Strep throat is caused by Streptococcus bacteria. The amount of bacteria multiplies at a rate of 10^13 per 10^2 hrs.

$10^2$ hours = $10^3$ bacteria

The amount of bacteria in one hours is,

$\text{Bacteria}=\frac{10^{13}}{10^2}$

The amount of bacteria after $10^3$ hours is,

$\text{Bacteria}=\frac{10^{13}}{10^2}\times (10^3)$

$\text{Bacteria}=10^{13}\times 10$

$\text{Bacteria}=10^{14}$

Therefore, the total amount of bacteria present after $10^3$ hours is $10^{14}$.