We are given
Tobias dropped a tennis ball from a height of 60 meters. The time in seconds it takes for the ball to fall 60 feet is 0.25(radical60).
so, time is
[tex]T=0.25\sqrt{60} =\frac{1}{4} \sqrt{60}[/tex]
we have to approximate it's value
First approximation set:
we know that
[tex]49<60<64[/tex]
we can take sqrt all the sides
[tex]\sqrt{49} <\sqrt{60} <\sqrt{64}[/tex]
we can simplify it
[tex]7 <\sqrt{60} <8[/tex]
Divide all sides by 4
[tex]\frac{7}{4}< \frac{1}{4} \sqrt{60} <\frac{8}{4}[/tex]
Second approximation set:
[tex]7.7<\sqrt{60} <7.8[/tex]
Divide all sides by 4
[tex]\frac{7.7}{4} <\frac{1}{4} \sqrt{60} <\frac{7.8}{4}[/tex]
[tex]1.925<\frac{1}{4} \sqrt{60} <1.95[/tex]
Third approximation set:
[tex]7.74<\sqrt{60} <7.75[/tex]
Divide all sides by 4
[tex]\frac{7.74}{4} <\frac{1}{4} \sqrt{60} <\frac{7.75}{4}[/tex]
[tex]1.935<\frac{1}{4} \sqrt{60} <1.9375[/tex]
so, we get
[tex]t=1.94seconds[/tex]......Answer