Question

Tomika uses 6 1/9 inches of wire to make a necklace and 3 1/3 inches of wire to make a bracelet. How many necklace and bracelet sets can she make if she uses 28 1/3 inches of wire in all? Enter your answer in the box.

Answer 1

Answer: There are 3 necklace and bracelet sets she can make .

Step-by-step explanation:

Since we have given that

Length of wire she used to make a necklace is given by

$6\frac{1}{9}\text{ inches }=\frac{85}{3}\text{ inches }$

Length of wire she used to make a bracelet is given by

$3\frac{1}{3}\text{ inches }=\frac{55}{3}\text{ inches }$

Total length of wire she is used  in all is given by

$28\frac{1}{3}\text{ inches }=\frac{10}{3}\text{ inches }$

Now, we calculate number of necklace and bracelet sets she can make ,

So,

$\text{ Number of bracelet and necklace }\\\\= \frac{\frac{85}{3}}{\frac{55}{9}+\frac{10}{3}}\\\\=\frac{\frac{85}{3}}{\frac{85}{9}}\\\\=3$

So, there are 3 necklace and bracelet sets she can make .

Answer 2

The number of braclet and necklace sets which can be made using the wire obtained using the division operation is 3.

Given the Parameters :

• 1 bracelet = $3 \frac{1}{3}$

• 1 necklace = $6 \frac{1}{9}$

• Total length of wire = $28 \frac{1}{3}$

Total length of wire required to make a set of necklace and bracelet :

• $3 \frac{1}{3} + 6 \frac{1}{9} = 9 \frac{4}{9}$

The number of bracelet and necklace set that can be made can be calculated thus :

• Total length of wire ÷ length of wire to make a set

Number of sets = $28 \frac{1}{3} \div 9 \frac{4}{9}$

Number of sets = $\frac{85}{3} \times \frac{9}{85} = 3$

Therefore, the Number of necklace and bracelet sets that can be made is 3.

Learn more : https://brainly.com/question/18112348