Question

A volleyball is full of pressurized air. The air temperature is 24.6˚C. The volleyball’s absolute pressure is 130.75 kilopascals, and its volume is 5.27 liters. How many moles of air are inside the volleyball?

A.
0.278 mol
B.
3.37 mol
C.
3.59 mol
D.
25.2 mol
E.
28.0 mol

Answer 1

Answer:

             0.278 mol

Solution:

Data Given:

                   Pressure  =  P  =  130.75 kPa  =  1.29 atm

                   Volume  =  V  =  5.27 L

                   Temperature  =  T  =  24.6 °C  =  297.75 K

                   Gas Constant  =  R  =  0.08215 atm.L.mol⁻¹.K⁻¹

Formula Used:

                   P V  =  n R T

Solving for "n",

                   n  =  P V / R T

Putting values,

             n  =  (1.29 atm × 5.27 L) ÷ (0.08215 atm.L.mol⁻¹.K⁻¹ × 297.75 K)

             n =  0.277 moles

Answer 2

Answer:

The answer is A(278).

Explanation:

we already know that ..

Pressure=P=  130.75 kPa  =  1.29 atm

Volume=V=  5.27 L

Temperature=T=  24.6 °C  =  297.75 K

Gas Constant=R=  0.08215 atm.L.mol⁻¹.K⁻¹

so the formula to be used is..

P V=n R T

but we have to solve for n so the new formula is..

n=P V / R T

we have to fill in the formula.. and answer it ..

n=(1.29 atm × 5.27 L) ÷ (0.08215 atm.L.mol⁻¹.K⁻¹ × 297.75 K)

n=688.837747 joules ÷ 2 478 425.97 m-1 kg s-2 K

n=0.278 moles

So the answer is A(278).