Question

When a 60 g (=0.06 kg) tennis ball is served by a newly invented machine, it accelerates from zero to 50 m/s. The ball experiences a constant acceleration due to the impact with the racket over a distance of 0.5 m. What is the

Answer 1

here tennis ball is accelerated from initial speed zero to final speed 50 m/s

In this accelerated motion the distance moved by the ball is 0.5 m

So here we can use kinematics to find the acceleration of the ball during this distance

$v_f^2 - v_i^2 = 2 a d$

here given that

vf = 50 m/s

vi = 0

d = 0.5 m

$50^2 - 0 = 2*a*0.5$

$2500 m/s^2 = a$

now if we have acceleration during its motion so we can find the applied force by using Newton's II law

$F = ma$

$F = 0.06*2500$

$F = 150 N$

now the applied force will be 150 N on the ball by racket