Respuesta :

Answer:

[tex]y\leq 3[/tex]

All real numbers less than or equal to 3

Step-by-step explanation:

we have

[tex]3y\leq 2y+3[/tex]

Solve for y

Subtract 2y both sides

[tex]3y-2y\leq 2y+3-2y[/tex]

[tex]y\leq 3[/tex]

The solution is the interval ------> (-∞,3]

All real numbers less than or equal to 3

In a number line the solution is the shaded area down of y=3 (close circle)

see the attached figure

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