Question

what is the distance between the points (1, -4) and (1, 0)

Answer 1

For this case we have that the distance between two points is given by:

$d = \sqrt{(y2-y1)^2+(x2-x1)^2}$

Given the points:

$(x1, y1) = (1, -4)(x2, y2) = (1,0)$

We substitute in the formula:

$d = \sqrt{(0 - (- 4)) ^ 2 + (1-1) ^ 2}$

$d = \sqrt{(4 ^ 2 + 0 ^ 2)}$

$d=\sqrt{16}$

$d = 4$

So, the distance is $d = 4$

Answer:

$d = 4$