[tex]\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{We have the points (-4, 0) and (4, -4)}\\\\\text{substitute:}\\\\m=\dfrac{-4-0}{4-(-4)}=\dfrac{-4}{8}=-0.5\\\\\text{therefore we have the equation of the given line in slope-intercept form:}\\y=-0.5x+b.\\\\\text{Parallel lines have the same slope.}\\\\\text{Therefore the line equation from question is y = -0.5x + b.}[/tex]
[tex]\text{It passes through the point (2, 3).}\\\\\text{Substitute the coordinates of the given point to the equation of the line}:\\\\3=-0.5(2)+b\\3=-1+b\qquad|+1\\4=b\to b=4\\\\\text{therefore}\ y=-0.5x+4\qquad|+0.5x\\\\0.5x+y=4\qquad|\cdot2\\\\\boxed{x+2y=8\to B.)}[/tex]
