Question

what is the value of the range of the function f(x) =2x2-3x+8 for the domain value3?

Answer 1

Given the function $f(x)=2x^2-3x+8.$

For the domain value x=3 you should find f(3). With this aim substitute instead x the value 3 into the function expression:

$f(3)=2\cdot 3^2-3\cdot 3+8=18-9+8=17.$

Answer: the value of the range f(3) is 17.

Answer 2

Answer

17

Explanation

The range of a function is the value resulting from the possible independent  variable x.  It is the value of y in a function for any given independent variable.

f(x) =2x²-3x+8

When the domain = 3

f(x) = 2(3)² - 3(3) + 8

     = 2×9 - 3×3 + 8

    = 18 - 9 + 8

    = 17