Question

There are now 100 carbon-14 atoms on the screen.  The half-life of carbon-14 is about 5700 years. If you left those 100 carbon-14 atoms to sit around for 5700 years, how many would you expect to decay during that time?

Answer 1

7 will decay after that it will be 3.5

Answer 2

Half-life is defined as the time taken for the radioactive element or isotope to fall to half of its original value. The half-life of the Carbon-14 will be 50.

Given that,

• N(t) = ?
• N₀ = 100
• t = 5700 years

where,

N(t) = quantity of the substance remaining

N₀ = initial quantity of the substance

t = time elapsed

$\text {t}_{1/2}$  = half-life of the substance

Since it is mentioned that the half-life of carbon -14 is 5700 years, and it is left to sit around for 5700 years then:

$\dfrac {\text t}{\text t}_{1/2}$   = $\dfrac{5700}{5700}$  = 1.

Substituting the values in the above formula:

N(t) = 100 x $\dfrac {1}{2}^{1}$

N (t) = 50

Therefore, the decay will be equal to 50.

To know more about half-life, refer to the following link:

https://brainly.com/question/21445950