Respuesta :

For this case we have the following expression:

[tex]12-2x-3y^5[/tex]

If [tex]x = 2[/tex]

[tex]y = -4[/tex]

We substitute the values in the given expression:

[tex]12-2 (2) -3 (-4) ^ 5 =[/tex]

We solve the operations that are inside the parentheses:

Applying law of power and law of signs we have:

[tex]12-4-3 ((- 4) (- 4) (- 4) (- 4) (- 4)) =[/tex]

Simplifying the operation within parentheses:

[tex]12-4-3 (-1024) =[/tex]

Multiplying:

[tex]12-4 + 3072 =[/tex]

Adding algebraically we have:

[tex]12-4 + 3072 = 3080[/tex]

Answer:

The value of [tex]12-2x-3y^5[/tex] for [tex]x = 2[/tex] and[tex]y = -4[/tex] is 3080.


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