Question

What is the equilibrium constant expression for the given system? CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

Answer 1

Answer:

• Kc =  [CH3OH]  ÷  [CO][H2]∧2

Explanation:

                         CO(g) + 2H(2)(g) <-----> CH(3)OH(g)

• Rate of forward reaction = Kf [CO][H2]∧2
• Rate of reverse reaction = Kr [CH3OH]

At equlibrium

                      Rate of forward = rate of reverse

                       Kf [CO][H2]∧2   =   Kr [CH3OH]  

                                         Kf/Kr =    [CH3OH]  ÷  [CO][H2]∧2

                                              Kc =  [CH3OH]  ÷  [CO][H2]∧2