as per the reaction we have
[tex]H_2 + O_2 ---> H_2O_2[/tex]
so here 1 mole of H2 react with 1 mole of O2 and give 1 mole of H2O2 as the product
now we will find the moles of given reactant
moles of H2
[tex]n_1 = \frac{2}{2} = 1 mole[/tex]
moles of O2
[tex]n_2 = \frac{32}{32} = 1 mole[/tex]
so here both present in 1 mole each hence the product will also formed 1 mole
so here we have
[tex]n = 1 mole[/tex] H2O2 will form
so mass of the product
mass = moles* molecular mass
[tex]m = 1 * (2 + 32)[/tex]
[tex]m = 34 g[/tex]
so the product mass will be 34 g