Respuesta :
The minimum value for the function [tex]y=x^{2} +6x+9[/tex] will be 0
What will be the minimum value of the function?
when we put the given values in the function [tex]y=x^{2} +6x+9[/tex]
At x=3 [tex](3^{2} )+(6\times3)+9=36[/tex]
At x=9 [tex](9^{2} )+(6\times9)+9=162[/tex]
At x=0 [tex]0+0+9=9[/tex]
At x=1 [tex]1+(1\times60+9=16[/tex]
So we can see that At x=0 the value of y will be maximum
Thus the minimum value for the function [tex]y=x^{2} +6x+9[/tex] will be 0
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