Respuesta :

the minimum value is 0

The minimum value for the function [tex]y=x^{2} +6x+9[/tex]  will be 0

What will be the minimum value of the function?

when we put the given values in the function [tex]y=x^{2} +6x+9[/tex]

At x=3    [tex](3^{2} )+(6\times3)+9=36[/tex]

At  x=9    [tex](9^{2} )+(6\times9)+9=162[/tex]

At  x=0    [tex]0+0+9=9[/tex]

At  x=1   [tex]1+(1\times60+9=16[/tex]

So we can see that At x=0 the value of y will be maximum

Thus the minimum value for the function [tex]y=x^{2} +6x+9[/tex]  will be 0

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