[tex]1.715 \times 10^{4} \; \text{years}[/tex]
Carbon-14 is radioactive and decays spontaneously. Interaction between stellar radiation and atmospheric nitrogen ensures a constant carbon-14 to carbon-12 ratio in the earth atmosphere. Living plants undergo respiration and take in carbon constantly and maintain a constant carbon-14-to-carbon-12 ratio in their tissues. Carbon atoms in wood artifacts are no longer refreshed such that the relative abundance of carbon-14 decays exponentially.
It takes one half-life for the relative abundance of carbon-14 in a sample to drop by one half. It would thus take three consecutive half-lives for the mass of carbon-14 in the wooden artifact to decrease by a factor of eight.
[tex]t_{1/2} = 5, 715 \; \text{years}[/tex] as seen in the question. Three half-lives would thus correspond to
[tex]3 \times 5,715 = 17145 = 1.715 \times 10^{4} \; \text{years}[/tex]
The age of this sample is therefore [tex]1.715 \times 10^{4} \; \text{years}[/tex] at most.