Question

You place a box weighing 216.5 N on an inclined plane that makes a 38.6 ◦ angle with the horizontal. Compute the component of the gravitational force acting down the inclined plane. Answer in units of N.

Answer 1

Answer:

The gravitational force acting down the inclined plane = 135.07 N

Explanation:

  The given figure shows the arrangement of box.

  The weight of box 216.5N can be resolved in to two,the vertical component of the gravitational force acting down the inclined plane and horizontal component of the gravitational force acting perpendicular to the inclined plane.

 The gravitational force acting down the inclined plane = Vertical component of weight of box.

                      = 216.5 sin 38.6 = 135.07 N

The gravitational force acting down the inclined plane = 135.07 N

Answer 2

The component of the gravitational force acting down the inclined plane is 135.07 N

Find the diagram of the question attached.

The force acting along the plane of the incline is opposite the frictional force and expressed using the formula shown below:

$F_m = Fsin \theta$

Given the following parameters

F = 216.5 N

$\theta$ = 38.6 degrees

Substitute the given parameters into the formula as shown:

$F_m = 216.5sin 38.6^0\\F_m=216.5(0.6239)\\F_m=135.07 N$

Hence the component of the gravitational force acting down the inclined plane is 135.07 N

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