Is it A) , B) , C), D) , E)
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Answer:
Part A) The statement is True
Part B) The statement is False
Part C) The statement is True
Part D) The statement is True
part E) The statement is False
Step-by-step explanation:
Part A) we have
[tex]1.66..=1 \frac{6}{9}[/tex]
The statement Is True
Convert the repeating decimal 1.66.. to an equivalent fraction
Let
[tex]x=1.66..\\ 10x=16.66..\\ 10x-x=16.66..-1.66..\\ 9x=15\\ x=15/9[/tex]
Convert to mixed number
[tex]15/9=9/9+6/9=1 \frac{6}{9}[/tex]
therefore
[tex]1.66..=1 \frac{6}{9}[/tex]
Part B) we have
[tex]0.6 < 6\%[/tex]
The statement is false
Because
[tex]6\%=6/100=0.06[/tex]
so
substitute
[tex]0.6 < 0.06[/tex] -----> is not true
Part C) we have
[tex]45\% \leq4.5[/tex]
The statement is True
Because
[tex]45\%=45/100=0.45[/tex]
substitute
[tex]0.45 \leq4.5[/tex] ----> is true
Part D) we have
[tex]5^{2} \geq 16[/tex]
The statement is True
Because
[tex]5^{2}=25[/tex]
substitute
[tex]25 \geq 16[/tex] ----> is true
Part E) we have
[tex]9.25 > 9\frac{3}{4}[/tex]
The statement is false
Because
Convert mixed number to an improper fraction
[tex]9\frac{3}{4}=\frac{9*4+3}{4}=\frac{39}{4}[/tex]
Convert decimal number to an improper fraction
[tex]9.25=9\frac{1}{4}=\frac{9*4+1}{4}=\frac{37}{4}[/tex]
substitute
[tex]\frac{37}{4} > \frac{39}{4}[/tex] -----> is not true