Question

graph y=sin^-1(1/4)x) on the interval -5<x<5

Answer 1

we are given

$y=sin^{-1}(\frac{1}{4}x)$

We can select some values between x=-5 and x=5

and then we can plug it and find y

after that we get points

and then we can locate it on the graph and join them to get graph

At x=-4:

$y=sin^{-1}(\frac{1}{4}(-4))$

$y=-1.5708$

point is (-4,-1.57080)

At x=-3:

$y=sin^{-1}(\frac{1}{4}(-3))$

$y=-0.84806$

point is (-3,-0.84806)

At x=-2:

$y=sin^{-1}(\frac{1}{4}(-2))$

$y=-0.52360$

point is (-2,-0.52360)

At x=-1:

$y=sin^{-1}(\frac{1}{4}(-1))$

$y=-0.25268$

point is (-1,0.25268)

At x=0:

$y=sin^{-1}(\frac{1}{4}(0))$

$y=0$

point is (0,0)

At x=1:

$y=sin^{-1}(\frac{1}{4}(1))$

$y=0.25268$

point is (1,0.25268)

At x=2:

$y=sin^{-1}(\frac{1}{4}(2))$

$y=0.52360$

point is (2,0.52360)

At x=3:

$y=sin^{-1}(\frac{1}{4}(3))$

$y=0.84806$

point is (3,0.84806)

At x=4:

$y=sin^{-1}(\frac{1}{4}(4))$

$y=1.57080$

point is (4,1.57080)

now, we can locate these values

we get our graph as

Answer 2

Answer:

D is the answer I just took the test.