Question

find the value of Sin^-1(tan (pi/4)) a.0 b.pi c.2 d.pi/2

Answer 1

we are given

$sin^{-1}(tan(\frac{\pi}{4}))$

Let's assume entire term as x

$sin^{-1}(tan(\frac{\pi}{4}))=x$

now, we can take both sides as sin

$sin(sin^{-1}(tan(\frac{\pi}{4})))=sin(x)$

since, sin and sin^-1 are inverse of each other

so, they will get cancelled

and we get

$tan(\frac{\pi}{4})=sin(x)$

now, we know that

tan(pi/4)=1

$1=sin(x)$

and sin is 1 at pi/2

so, we get

$x=\frac{\pi}{2}$

so, option-D.........Answer

Answer 2

Answer:

D

Step-by-step explanation: