Question

Point C ∈ AB , AB = 33 cm. Point C is 2 times farther from point B than from point A. Find AC and CB. Please Help.

Answer 1

answer: AC = 11; CB = 22
solution:
AC = 1
CB = 2 (just to help visualize)
1 + 2 = 3
33/3 = 11
11 * 1 = 11 = AC
11 * 2 = 22 = CB

Answer 2

AC    =   11 cm,  and CB   =   22 cm

Since C ∈ AB, this means that C is located at a point between A and B

AC  +   CB   =   AB...........(*)

AB   =  33 cm

Point C is 2 times farther from point B than from point A.

This can be expressed mathematically as:

CB   =   2AC

Substitute CB = 2AC into equation (*)

AC   +  CB   =  AB

AC   +   2AC   =   AB

3AC    =   AB

3AC    =    33

AC     =   33/3

AC    =   11 cm

Substitute AC = 11, and AB = 33 into equation (*)

AC   +  CB   =  AB

11   +    CB    =   33

CB    =  33  -  11

CB   =   22 cm

Therefore, AC    =   11 cm and CB   =   22 cm

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