Question

a large conical mound of sand with a diameter of 45 ft and height of 15 ft is being stored as a key raw ingredient for products at your glass manufacturing company. What is the approximate value of the mound?

Answer 1

V=1/3(pi r^2 h)
45/2=22.5:(radius)
22.5^2=506.25:(r^2)
pi 506.25=1590.43:(pi r^2)
1590.43*15=23856.45:(pi r^2h)
1/3*23856.45=7952.15:(1/3(pi r^2h))
V= about 7952.15

Answer:A) 7948

Answer 2

Answer:

A. 7,948 cubic feet

Step-by-step explanation:Volume of a cone ≈ (3.14 × (radius × radius)× height) /3