Question

find the value of 2^-3*3^-2

Answer 1

$2^{-3}\cdot 3^{-2}$

$2^-3=\frac{1}{2^3}$

$3^-2=\frac{1}{3^2}$

$\frac{1}{2^3}*\frac{1}{3^2}$

$\frac{1*1}{2^3*3^2}$

$2^3*3^2=72$

$=\frac{1}{72}$

Hope this helps!

Thanks!

-Charlie