Question

How many sulfur atoms are present in 25.6 g of Al2(S2O3)3

Answer 1

Given the mass of $Al_{2}(S_{2}O_{3})_{3}$=25.6 g

The molar mass of $Al_{2}(S_{2}O_{3})_{3}$=390.35g/mol

Converting mass of $Al_{2}(S_{2}O_{3})_{3}$to moles:

$25.6 g Al_{2}(S_{2}O_{3})_{3}*\frac{1molAl_{2}(S_{2}O_{3}}{390.35 gAl_{2}(S_{2}O_{3}} =0.0656molAl_{2}(S_{2}O_{3}$

Converting mol $Al_{2}(S_{2}O_{3})_{3}$to mol S:

$0.0656mol Al_{2}(S_{2}O_{3})_{3}*\frac{6molS}{1mol Al_{2}(S_{2}O_{3})_{3}}=0.3936 molS$

Converting mol S to atoms of S using Avogadro's number:

1 mol = $6.022*10^{23}atoms$

$0.3936mol S *\frac{6.022*10^{23}atoms S}{1 mol S}=2.37*10^{23} S atoms$

Answer 2

Sulfur is a chemical element with symbol S. It is found in the in the group 16. It has atomic number 16 and atomic mass as 32 units. In the compound $\text{Al}_2(\text{SO}_3)_3$ there are 2.37 x $10^{23}$ atoms of sulfur are present.

Given that,

• Mass of $\text{Al}_2(\text{SO}_3)_3$ = 25.6 g
• Molar mass of $\text{Al}_2(\text{SO}_3)_3$ = 390.35 g/mol
• According to the formula of number of moles:

$\begin{aligned}\text{n}&=\frac{\text{mass}}{\text{molar mass}}\end{aligned}$

Now, converting mass of $\text{Al}_2(\text{SO}_3)_3$ into moles, we get:

• $\begin{aligned}\25.6\;\text{g}[\text{Al}_2(\text{S}_2\text{O}_3)]\times\frac{1\text{mol\;Al}_2\text{S}_2\text{O}_3}{390.35\;\text{g}\;\text{Al}_2(\text{S}_2\text{O}_3)}&=0.0656\;\text{mol}\;\text{Al}_2(\text{S}_2\text{O}_3)\end{aligned}$

Similarly, for sulphur:

• $\begin{aligned}\0.0656\;\text{mol}\;[\text{Al}_2(\text{S}_2\text{O}_3)_3]\times\frac{6\;\text{mol\;S}}{1\;\text{mol}\;\text{Al}_2(\text{S}_2\text{O}_3)_3}&=0.3936\;\text{mol\;S}\end{aligned}$

From the Avogadro's number, we know that,

• 1 mole = 6.022 $\times 10^{23}$ atoms.

Now, 0.3936 moles of sulphur will have:$\begin{aligned}0.3936\;\text{mol\;S}\times\frac{6.022\times10^{23}\text{atoms\;S}}{1\;\text{mol\;S}}&=2.37\times10^{23}\;\text{S\;atoms}\end{aligned}$

Therefore, the number of atoms of sulphur in the compound $\text{Al}_2(\text{SO}_3)_3$ is 2.37 $\times 10^{23}$.

To know more about number of moles, refer to the following link:

https://brainly.com/question/13332140?referrer=searchResults