Respuesta :
Since the box is cube-shaped, its volume is V = 30 ft^2 = s^3, where s is the length of one side. Then s = ∛30, or approx. 3.11 ft. The length of one side of the 9 ft^2 square poster is √9, or 3 ft. Yes, the 3 ft^2 poster will fit the box, whose bottom area is 3.11 ft^2.
Answer:
Yes, the poster lie flat in the box.
Step-by-step explanation:
Consider the provided information.
Talia is packing a moving box. She has a square-framed poster with an area of 9 square feet.
The area of square = (side)²
Thus, the side of the poster frame is:
9 = (side)²
√9 = side
side = 3
Take positive value as side should be a positive number.
The side of the poster frame is 3 feet.
The cube-shaped box has a volume of 30 cubic feet.
Volume of cube = (side)³
Thus, the side of cube-shaped box is:
30 = (side)³
∛30 = side
side ≈ 3.12
The side of cube-shaped box 3.12 feet.
3.12 feet is greater than 3 feet. That means the side of the cube shaped box is greater than side of the poster frame.
Hence, the poster lie flat in the box.