Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization energy (kJ/mol) Electron affinity (kJ/mol) Electronegativity Sb 145 ? –103 2.05 I 140 1008 –295 ? Which predictions can most likely be made? Sb has a lower ionization energy but a higher electronegativity than I. Sb has a higher ionization energy but a lower electronegativity than I. Sb has a lower ionization energy and a lower electronegativity than I. Sb has a higher ionization energy and a higher electronegativity than I.

Respuesta :

Sb has a lower ionization energy and a lower electronegativity  than I.

Antimony has a lower ionization energy and a lower electronegativity than iodine atom in the periodic table.

How atomic radius is related to electronegativity ?

Electronegativity as well as ionization potential and enthalpy of any atom is inversely proportional to the atomic radius of that atom.

As size of any atom decreases the power of nucleus to the outermost electron will increases which in turn results to the high electronegativity, high ionization potential and high electron affinity. In the question it is given that atomic radius of antimony is large i.e. 145pm as compared to the atomic radius of iodine i.e. 140pm. Hence, the electronegativity, electron affinity and ionization potential of antimony atom is less.

Hence, option (3) is correct.

To know more about atomic radius, visit the below link:

https://brainly.com/question/1379215

RELAXING NOICE
Relax