Question

What is the solution set of x2 – 10 = 30x? {–220, 250} {–250, 220} {15 – , 15 + } {–15 – , –15 + }

Answer 1

x^2 - 10 = 30x

x^2 = 30x + 10

x^2 - 30x = 10

x^2 - 30x + 225 = 235

(x - 15)^2 = 235

x - 15 = √235

x = 15 ± √235 is the solution set.

Answer 2

We want to get the solution set for the quadratic equation:

x^2 -10 = 30x.

The solution set is:

{15 - √235, 15 + √235}

We need to solve the equation:

x^2 - 10 = 30x

To solve this, first, we need to move all the terms to the same side of the equation, I will move all the terms to the left side, so we get:

x^2 - 30x - 10 = 0

Now we can use the Bhaskara's formula to solve this, remember that for a general quadratic equation:

a*x^2 + b*x + c = 0

The solutions are:

$x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}$

Then for our equation, the solutions are:

$x = \frac{-(-30)\pm \sqrt{(-30)^2 - 4*1*(-10)} }{2*1} \\\\\\x =15 \pm \sqrt{ \frac{30^2 + 4*10}{4} }\\\\x = 15 \pm \sqrt{235}$

Then the solution set is:

{15 - √235, 15 + √235}

If you want to learn more, you can read:

https://brainly.com/question/17177510