Respuesta :
Easiest way to solve these problems would be setting up a proportion.
[tex]\frac{27}{6} = \frac{x}{2}[/tex]
Let x = ... well... our missing x
Now, we crossmultiply.
6x = 27(2)
6x = 54
x = 54/6
x = 9
Variations can be direct, inverse or joint variation.
The value of x when y = 2, is 9.
The variation is given as:
[tex]\mathbf{x\ \alpha\ y}[/tex]
Express as an equation
[tex]\mathbf{x= ky}[/tex]
x = 27, when y = 6.
So, we have:
[tex]\mathbf{27= 6k}[/tex]
Divide both sides by 6
[tex]\mathbf{4.5 = k}[/tex]
Rewrite as:
[tex]\mathbf{k = 4.5 }[/tex]
When y = 2, we have:
[tex]\mathbf{x= ky}[/tex]
Substitute values for k and y
[tex]\mathbf{x = 4.5 \times 2}[/tex]
[tex]\mathbf{x = 9}[/tex]
Hence, the value of x when y = 2, is 9.
Read more about variations at:
https://brainly.com/question/24142249
