Respuesta :

ktreyb

Easiest way to solve these problems would be setting up a proportion.

[tex]\frac{27}{6} = \frac{x}{2}[/tex]

Let x = ... well... our missing x

Now, we crossmultiply.

6x = 27(2)

6x = 54

x = 54/6

x = 9

Variations can be direct, inverse or joint variation.

The value of x when y = 2, is 9.

The variation is given as:

[tex]\mathbf{x\ \alpha\ y}[/tex]

Express as an equation

[tex]\mathbf{x= ky}[/tex]

x = 27, when y = 6.

So, we have:

[tex]\mathbf{27= 6k}[/tex]

Divide both sides by 6

[tex]\mathbf{4.5 = k}[/tex]

Rewrite as:

[tex]\mathbf{k = 4.5 }[/tex]

When y = 2, we have:

[tex]\mathbf{x= ky}[/tex]

Substitute values for k and y

[tex]\mathbf{x = 4.5 \times 2}[/tex]

[tex]\mathbf{x = 9}[/tex]

Hence, the value of x when y = 2, is 9.

Read more about variations at:

https://brainly.com/question/24142249

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