Question

a cylinder with a 10 inch bore and a 24in stroke must move a 78540 lb load through its truck in 3 seconds How much hydraulic horsepower must be delivered to the cylinder?

Answer 1

We are given that the stroke is 24 inches. Therefore, the distance travelled will be given by $d=24$ inches.

Now, the force given to us is $F=78540$ lb.

Therefore, the work done will be:

$W=F\times d=78540 \times 24=1884960$ lb-in.

Now, Let "P" be the power and "t" be the time.

The time, t given to us is t=3 seconds.

We also know that $P=\frac{W}{t} =\frac{1884960}{3}=628320$ lb-in/s...Equation 1

Now, to find the power delivered in horsepower (hp), we will have to convert the Equation 1 to it's equivalent is hp.

Now, we know that 1 lb-in/s=$\frac{1}{6600}$ hp

Therefore, 628320 lb-in/s=$\frac{628320}{6600}= 95.2$ HP

Thus, the required answer in HP is 95.2 HP.