given that
acceleration = - 0.50 m/s^2
v = 13.5 m/s
so final speed will become zero after it completely stop
so here we can use kinematics
[tex]v_f = v_i + at[/tex]
[tex]0 = 13.5 - 0.50 * t[/tex]
[tex]13.5 = 0.5 * t[/tex]
[tex]t = 27 s[/tex]
so cycle will completely stop after t = 27 s