Respuesta :
for this question you should know that:
2/3 = 8/12
and
3/4 = 9/12
so now you can say:
7/12 < 8/12 < 9/12
so:
7/12 < 2/3 < 3/4 :)))
i hope this is helpful
have a nice day
2/3 = 8/12
and
3/4 = 9/12
so now you can say:
7/12 < 8/12 < 9/12
so:
7/12 < 2/3 < 3/4 :)))
i hope this is helpful
have a nice day
Forget the numerators, focus on the denominators for now. 3 an 4 are both multiples of 12, so we can multiply [tex] \frac{2}{3} [/tex] by 4 and [tex] \frac{3}{4} [/tex] by 3 to make all the fractions out of 12. This should make it easier to understand which one is the smallest / biggest.
[tex] \frac{2}{3} [/tex] × 4 = [tex] \frac{8}{12} [/tex]
[tex] \frac{3}{4} [/tex] × 3 = [tex] \frac{9}{12} [/tex]
You leave [tex] \frac{7}{12} [/tex] as it is because it's already out of 12.
Now you can see that obviously, [tex] \frac{3}{4} [/tex] is the largest fraction, as 9 is the biggest when it's out of 12. [tex] \frac{2}{3} [/tex] is the second largest as it's 8 out of 12, which is smaller than 9 but bigger than 7. Obviously, the last is one is [tex] \frac{7}{12} [/tex].
So the order is:
[tex] \frac{3}{4} [/tex], [tex] \frac{2}{3} [/tex], [tex] \frac{7}{12} [/tex].
[tex] \frac{2}{3} [/tex] × 4 = [tex] \frac{8}{12} [/tex]
[tex] \frac{3}{4} [/tex] × 3 = [tex] \frac{9}{12} [/tex]
You leave [tex] \frac{7}{12} [/tex] as it is because it's already out of 12.
Now you can see that obviously, [tex] \frac{3}{4} [/tex] is the largest fraction, as 9 is the biggest when it's out of 12. [tex] \frac{2}{3} [/tex] is the second largest as it's 8 out of 12, which is smaller than 9 but bigger than 7. Obviously, the last is one is [tex] \frac{7}{12} [/tex].
So the order is:
[tex] \frac{3}{4} [/tex], [tex] \frac{2}{3} [/tex], [tex] \frac{7}{12} [/tex].