contestada

50 J of work was performed in 20 seconds. how much power was used to do this task?

Respuesta :

AL2006

             Power = (amount of work done) / (time to do the work).

                         =                    (50 J)          /        (20 sec)

                         =      2.5 joule/sec  =  2.5 watts .

The Correct answer to this question for Penn Foster Students is: 2.5 W