Question

Dana has only nickels in her hand and Ajah has exactly the same number of dimes and no other coins. Together they have a total of 90¢. How many coins is each person holding?

Answer 1

They would each be holding 6 coins

Answer 2

Building and solving an equation, it is found that each person is holding 6 coins.

• We don't know the number of coins, so we call it x.
• A nickel is worth $0.05, thus in total, Dana has 0.05x.
• A dime is worth $0.1, thus in total, Ajah has 0.1x.
• Together, they have 0.9, thus:

$0.05x + 0.1x = 0.9$

$0.15x = 0.9$

$x = \frac{0.9}{0.15}$

$x = 6$

Each person is holding 6 coins.

A similar problem is given at https://brainly.com/question/17096268