Respuesta :

gmany

[tex]\dfrac{1}{(x^4)^{-2}}\\\\_{\text{use}\ (a^n)^m=a^{nm}}\\\\=\dfrac{1}{x^{(4)(-2)}}=\dfrac{1}{x^{-8}}\\\\_{\text{use}\ a^{-n}=\frac{1}{a^n}}\\\\=\dfrac{1}{\dfrac{1}{x^8}}=x^8\\\\Answer:\ \dfrac{1}{(x^4)^{-2}}=x^8[/tex]

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