Respuesta :

we are given

[tex]f(x)=\frac{1}{x}[/tex]

[tex]g(x)=\sqrt{x+5}[/tex]

Calculation of (f/g)(x):

[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}[/tex]

now, we can plug values

[tex](\frac{f}{g})(x)=\frac{\frac{1}{x}}{\sqrt{x+5}}[/tex]

now, we can simplify it

[tex](\frac{f}{g})(x)=\frac{1}{x\sqrt{x+5}}[/tex]

Domain:

we know that domain is all possible values of x for which any function is defined

function will be undefined when denominator =0

[tex]x\sqrt{x+5} =0[/tex]

[tex]x=-5,x=0[/tex]

we are given sqrt function

and we know that value inside sqrt will always be greater than 0

[tex]x+5>0[/tex]

[tex]x>-5[/tex]

so, domain will be

[tex](-5,0)U(0,\infty)[/tex]..............Answer