we are given
[tex]f(x)=\frac{1}{x}[/tex]
[tex]g(x)=\sqrt{x+5}[/tex]
Calculation of (f/g)(x):
[tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}[/tex]
now, we can plug values
[tex](\frac{f}{g})(x)=\frac{\frac{1}{x}}{\sqrt{x+5}}[/tex]
now, we can simplify it
[tex](\frac{f}{g})(x)=\frac{1}{x\sqrt{x+5}}[/tex]
Domain:
we know that domain is all possible values of x for which any function is defined
function will be undefined when denominator =0
[tex]x\sqrt{x+5} =0[/tex]
[tex]x=-5,x=0[/tex]
we are given sqrt function
and we know that value inside sqrt will always be greater than 0
[tex]x+5>0[/tex]
[tex]x>-5[/tex]
so, domain will be
[tex](-5,0)U(0,\infty)[/tex]..............Answer