Given: PQ ⊥ QR , PR=20, SR=11, QS=5 Find: The value of PS.
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1. PQR and is a right triangle, so you can calculate the measure of PQ by applying the Pythagorean Theorem. PR is the hypotenuse and QR and PQ are the legs:
[tex]PR^{2}=PQ^{2}+QR^{2}\\ PQ=\sqrt{PR^{2}-QR^{2}}\\ PQ=\sqrt{20^{2}-16^{2}} \\ PQ=12[/tex]
2. PQS and is a right triangle too, so you can calculate the measure of PS by applying the Pythagorean Theorem as above. PS is the hypotenuse and PQ and QS are the legs:
[tex]PS=\sqrt{PQ^{2}+QS^{2}}=13[/tex]
Therefore, the answer is: The value of PS is 13.
Answer:
1. PQR and is a right triangle, so you can calculate the measure of PQ by applying the Pythagorean Theorem. PR is the hypotenuse and QR and PQ are the legs:
2. PQS and is a right triangle too, so you can calculate the measure of PS by applying the Pythagorean Theorem as above. PS is the hypotenuse and PQ and QS are the legs:
Therefore, the answer is: The value of PS is 13.
Step-by-step explanation: